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- Teorie transformare baze
- f(x) = transf din baza 16 in baza 10
- f(123)=f(12)*16+3 =(1*16+2)*16 +3
- f(12)=f(1)*16+2 =1*16+2
- f(1)=1
- B16 --> B10
- 2E5F9 = (((2*16^1 +14)*16^1 + 5*)16^1 + 15)*16^1 + 9
- 4 3 2 1 0
- = 2*
- (2E5F9)16=(43210)10
- 5123=((5*16^1 +1)*16^1 + 2)*16^1 + 3
- 4321=4000+300+20+1=((4*10+3)*10+2)*10+1
- B2 --> B10
- 11011=1*2^4+1*2^3+0*2^2+1* 2^1+1*2^0
- 43210
- 0 0
- 1 1
- 2 2
- 3 3
- 4 4
- 5 5
- 6 6
- 7 7
- 8 8
- 9 9
- A 10
- B 11
- C 12
- D 13
- E 14
- F 15
- 10
- (73)10 = (?)16
- 73:16 9*1 nr=nr+c*p
- 4:16 4*10
- 0
- (73)10 = (49)16
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