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Farz0l1x
Sep 3rd, 2022
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for n in range(1, 1000):
n_2 = bin(n)[2:]
if int(n_2) % 2 == 0:
n_2 = n_2 + '10'
else:
n_2 = '1' + n_2 + '01'
R = int(n_2 , 2)
if R > 441:
print(n)
break
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