Farz0l1x

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Sep 3rd, 2022
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  1. for n in range(1, 1000):
  2. n_2 = bin(n)[2:]
  3. if int(n_2) % 2 == 0:
  4. n_2 = n_2 + '10'
  5. else:
  6. n_2 = '1' + n_2 + '01'
  7. R = int(n_2 , 2)
  8. if R > 441:
  9. print(n)
  10. break
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