Advertisement
Guest User

Untitled

a guest
Jun 15th, 2022
45
0
Never
Not a member of Pastebin yet? Sign Up, it unlocks many cool features!
SQL 0.27 KB | None | 0 0
  1. SELECT surname,firstname,attr.*
  2. FROM borrowers
  3. LEFT JOIN (
  4.   SELECT borrowernumber,
  5.   MAX(CASE WHEN code = 'PROFESSION' THEN attribute ELSE NULL END) AS PROFESSION,
  6.   --autres attributs
  7.   FROM borrower_attributes
  8.   GROUP BY borrowernumber
  9. ) AS attr USING (borrowernumber);
Advertisement
Add Comment
Please, Sign In to add comment
Advertisement