$w = mysqli_query($con,"SELECT age, percent FROM drive03_2_monthly_income WHERE birthYear='1956' AND (age LIKE '%.00%') ORDER BY birthYear,age ");

$row = mysqli_fetch_array($w);
    for($n=0;$n<9;$n++) {
        echo $row[$n]->age." -- ".$row[$n]->percent."<br />";
        }