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May 25th, 2018
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  1. HypergeometricPFQ[{Subscript[a, 1], Subscript[a, p]}, {Subscript[b,
  2. 1], Subscript[b, q]},
  3. c z] HypergeometricPFQ[{Subscript[[Alpha], 1],
  4. Subscript[[Alpha], r]}, {Subscript[[Beta], 1],
  5. Subscript[[Beta], s]}, d z] == !(
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