# def is_leap_and_29Feb(s):
    # Some ways to deal with leap years.
    # In reality, what we want to do is remove Feb29, but add the daily
    #    return to the figure from the 28th - we shouldn't lose the data.

    # df.drop(df.index[['2012-02-29']])
    # df = df[~((df.index.month == 2) & (df.index.day == 29))]
    # df = df[~df.index.str.endswith('02-29')]
    # def _292(date): return (date.month==2) & (date.day==29)
    #    df['DATE'][df['DATE'].apply(_292)]-=pd.Timedelta('1D') # yesterday
    # if calendar.isleap(year):
    #    do_stuff
    # else:
    #    do_other_stuff

    # mask = is_leap_and_29Feb(df)
    # print mask
    #[False False False False False  True False False False  True]
    # print df.loc[~mask]
    #return (s.index.year % 4 == 0) &
    #    ((s.index.year % 100 != 0) | (s.index.year % 400 == 0)) &
    #    (s.index.month == 2) & (s.index.day == 29)