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Jun 20th, 2019
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  1. SELECT F.RASSOC,
  2. (SELECT COUNT(DTENG)
  3. FROM PARHLISE
  4. WHERE FORNECE = F.CODIGO) AS TOTAL_PARHLISE,
  5.  
  6. (SELECT COUNT(P.DTENG)
  7. FROM PARHLISE AS P
  8. INNER JOIN HISTLISE AS H ON H.FORNECE = P.FORNECE
  9. WHERE P.FORNECE = F.CODIGO AND P.DTENG > H.DTEMI) AS PARHLISE_ATRASO
  10.  
  11. FROM FORNECED AS F
  12. LEFT JOIN PARHLISE AS PH ON PH.FORNECE = F.CODIGO
  13. LEFT JOIN PARCLISE AS PC ON PC.FORNECE = F.CODIGO
  14. GROUP BY F.CODIGO, F.RASSOC
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