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- 1-
- SELECT *
- FROM Employee
- ORDER BY lName, fName
- 2-
- SELECT *
- FROM Employee
- WHERE sex = ‘feminino’
- 3-
- SELECT fName, lName, address
- FROM Employee as E
- INNER JOIN Department as D
- ON E.empNo = D.mgrEmpNo
- 4-
- SELECT fName, lName, address
- FROM Employee as E
- NATURAL JOIN Department as D
- WHERE D.deptName = 'IT'
- 5-
- SELECT fName, lName
- FROM Employee as E
- NATURAL JOIN WorksOn as W
- JOIN Project as P
- ON W.projNo = P.projNo
- WHERE P.projName = 'SCCS'
- 6-
- SELECT *
- FROM Employee as E
- JOIN Department as D
- ON E.empNo = D.mgrEmpNo
- WHERE
- E.DOB <= date('1955-12-31')
- ORDER BY lName
- 7-
- SELECT COUNT(empNo) as Total
- FROM Employee
- JOIN Department as D
- ON D.mgrEmpNo = Employee.empNo
- AND Employee.fName = 'James' and Employee.lName = 'Adam';
- 8-
- SELECT Employee.empNo, SUM(hoursWorked) AS Hours_Worked
- FROM Employee
- JOIN Department
- ON Employee.deptNo = Department.deptNo
- JOIN WorksOn
- ON Employee.empNo = WorksOn.empNo
- GROUP BY Employee.empNo
- ORDER BY Department.deptName, Employee.lName
- 9-
- SELECT projName, projNo, count(empNo) as numEmpregados
- FROM Project as P
- JOIN WorksOn as W
- ON p.projNo = W.projNo
- GROUP BY W.projNo
- HAVING numEmpregados>2
- 10-
- SELECT deptNo, count(empNo) as TOTAL_EMPREGADOS
- FROM Employee
- GROUP BY deptNo
- HAVING TOTAL_EMPREGADOS>10
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