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24 паттерн с остатками

nq1s788
Nov 13th, 2024
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  1. s = open('').readline()
  2. d = 0
  3. answ = 0
  4. p = 'XYZ'
  5. for i in range(len(s)):
  6.     if s[i] == p[d % 3]:
  7.         d += 1
  8.         answ = max(answ, d)
  9.     else:
  10.         d = 0
  11. print(answ)
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