squareroot python

# program to find square root of a integer number without using square root function
import time
def squareRoot(number,sqroot):

    # setting answer to be accurate upto 6 decimal places
    # change this to get more accuracy
    error = 0.000001

    # calculating num
    num = number/sqroot
    # till the difference is greater than error keep taking average
    while abs(num-sqroot) > error:
        sqroot = (sqroot+num)/2
        num = number/sqroot
        print(sqroot)
        print(num)
        # if num and sqroot are equal then we directly print the answer
        if num == sqroot:
            break

    print("The Square Root of " + str(number) + " is " + str(sqroot))
    return

# main function
cont = True
while(cont):

    number = float(input("Enter the number whose square root is to be found : "))

    #if the number is less than 0 then ask user to enter another number
    while number < 0:
        print("Enter a number greater than 0")
        number = int(input("Enter the number whose square root is to be found : "))

    # if the number is 0 or 1 then the answer is also is also 0 or 1
    if number == 0 or number == 1:
        print("The Square Root of " + str(number) + " is " + str(number))

    # else take initial guess from the user
    else:
        sqroot = int(input("Enter the initial guess : "))
        sqroot = sqroot%number
        squareRoot(number,sqroot)

    n = int(input("Do you want to enter another number (1/0): "))
    if n == 0:
        cont = False