https://www.spoj.com/problems/CSUMQ/

#include<bits/stdc++.h>
using namespace std;
typedef long long ll;

#define sp(y) fixed<<setprecision(y)
#define w(t) int t;cin>>t;while(t--)
#define pi 2*acos(0.0)
#define bg begin()
#define en end()
#define all(x) x.begin(),x.end()
#define sortarr(x) sort(x,x+arrsize(x))
#define arrsize(x) sizeof(x)/sizeof(x[0])
#define sortall(x) sort(all(x))
#define formn(m,n) for(m;m<=n;m++)
#define mp make_pair
#define pb push_back
#define vi vector<ll>
#define vs vector<string>
#define REP(i,a,b) for (int i=a;i<=b;i++)
#define sq(a) (a)*(a)
#define inparr(arr) for(auto &x: arr){cin>>x;}
#define printarr(arr) for(auto x: arr){cout<<x<<" ";}
#define nline "\n"
//iterative

//recursive
ll pow(ll c,ll d){return d==0?1:c*pow(c,d-1);}
ll gcd(ll a,ll b) {return b==0? a:gcd(b,a%b);}
ll lcm(ll a,ll b) {return ((a*b)/gcd(a,b));}
ll modpow(ll a,ll b,ll m){if(b==0){return 1%m;}ll res = modpow(a,b/2,m);res = (res*res) %m;if(b%2==1){res = (res*a) %m;}return res;}
ll modpoweritterative(ll a,ll n,ll m){ll ans=1;while(n>=1){if(n%2==0){a = (1ll * a * a ) %m;n/=2;}else{ans =(1ll * a * ans ) % m;n--;}}return ans;}
ll modinverse(ll a,ll m){ return modpoweritterative(a,m-2,m); }

//fast I/o;
void fastIO(){
     ios_base::sync_with_stdio(false);
     cin.tie(NULL);

}
void init_code(){
    fastIO();
     #ifdef EPSILON
    freopen("input.txt","r",stdin);
    freopen("output.txt","w",stdout);
     #endif

}

//solution
#define mx 100005
#define mod 1000000007
int sum[mx];


void solve(){
     int n,m;
     cin>>n;
     int arr[n];
     inparr(arr);
     for(int i=0;i<n;++i)
     {
          if(i==0){
               sum[i]=arr[i];
          }else{
                sum[i]=sum[i-1]+arr[i];

          }

     }
     cin>>m;
     for(int i=0;i<m;i++){
          int a,b;
          cin>>a>>b;
          cout<<sum[b]-sum[a-1]<<endl;
     }



}
//end solution
int main(){



     init_code();
     solve();
     return 0;
}