AboveTheMainDiagonal - JavascriptModule0

// Above the Main Diagonal - 100 out of 100, only if N is BigInt :) Otherwise - 93.33 out of 100
// You are given a square matrix of numbers, formed by powers of 2. See example

// Example: N = 4

//  1  2  4  8
//  2  4  8 16
//  4  8 16 32
//  8 16 32 64
// You task is to find the sum above the main diagonal
// The result is: 2 + 4 + 8 + 8 + 16 + 32 = 70
// Input
// Read from the standard input
// On the first line, read the number N
// The number of rows and columns
// Output
// Print to the standard output
// On the first line, print the sum of the numbers above the main diagonal except the diagonal
// Sample tests
// Input
// 4
// Output
// 70
const input = ['5'];
const print = this.print || console.log;
const gets = this.gets || ((arr, index) => () => arr[index++])(input, 0);
let n = +gets();
let sum = 0;
let arr;
const a1 = [];
for (let i = 0; i <= n - 1; i++) {
  arr = [];
  for (let j = 0; j <= n - 1; j++) {
    arr.push(Math.pow(2, j));
  }
  a1.push(arr.map(x => x * Math.pow(2, i)));
}
// print(a1); just checking how numbers look like
n = BigInt(n);
sum = BigInt(sum);
for (let i = BigInt(0); i < n - BigInt(1); i++) {
  for (let j = BigInt(i) + BigInt(1); j <= n - BigInt(1); j++) {
    sum += BigInt(a1[i][j]);
  }
}
print(String(sum));