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Aug 6th, 2012
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  1. find and replace repeating string in database
  2. [data attr1='2300.48' attr1='1' attr1='1116.95' attr1='60.75' attr1='9.22' attr1='' attr1='0' attr1='3593.39' attr1='119.05' attr1='25.96' attr1='27.98' attr1='36.32']
  3.  
  4. [data attr1='2300.48' attr1='1' attr1='1116.95' attr1='60.75' attr1='9.22' attr1='' attr1='0' attr1='3593.39' attr1='119.05' attr1='25.96' attr1='27.98' attr1='36.32']
  5.  
  6. [data attr1='2300.48' attr1='1' attr1='1116.95' attr1='60.75' attr1='9.22' attr1='' attr1='0' attr1='3593.39' attr1='119.05' attr1='25.96' attr1='27.98' attr1='36.32']
  7.  
  8. [data attr1='2300.48' attr1='1' attr1='1116.95' attr1='60.75' attr1='9.22' attr1='' attr1='0' attr1='3593.39' attr1='119.05' attr1='25.96' attr1='27.98' attr1='36.32']
  9.  
  10. [data attr1='2300.48' attr1='1' attr1='1116.95' attr1='60.75' attr1='9.22' attr1='' attr1='0' attr1='3593.39' attr1='119.05' attr1='25.96' attr1='27.98' attr1='36.32']
  11.  
  12. the text of the article
  13. [data.... ]
  14. [data.... ]
  15. [data.... ]
  16.  
  17. select distinct mycolumn from mytable;
  18.  
  19. select mycolumn from mytable group by mycolumn;
  20.  
  21. DELETE t
  22. FROM t
  23. LEFT JOIN t AS t2 ON (t.content = t2.content AND t.id > t2.id)
  24. WHERE t2.id;
  25.  
  26. SELECT * FROM t;
  27. +----+---------+
  28. | id | content |
  29. +----+---------+
  30. | 1 | abc |
  31. | 5 | abc123 |
  32. | 9 | abc123 |
  33. | 13 | abc |
  34. | 17 | abc |
  35. +----+---------+
  36.  
  37. SELECT * FROM t;
  38. +----+---------+
  39. | id | content |
  40. +----+---------+
  41. | 1 | abc |
  42. | 5 | abc123 |
  43. +----+---------+
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