Advertisement
Guest User

Untitled

a guest
Mar 24th, 2019
70
0
Never
Not a member of Pastebin yet? Sign Up, it unlocks many cool features!
text 1.97 KB | None | 0 0
  1. #include<bits/stdc++.h>
  2. #include<ext/pb_ds/assoc_container.hpp>
  3. using namespace __gnu_pbds;
  4. using namespace std;
  5. typedef long long ll;
  6. typedef long double ld;
  7. template<typename T>
  8. using ordered_set = tree<T, null_type, less_equal<T>, rb_tree_tag, tree_order_statistics_node_update>;
  9. #define X first
  10. #define Y second
  11. #define sz(a) (int)a.size()
  12. #define pb push_back
  13.  
  14. void solve();
  15.  
  16. int main() {
  17. // freopen("schools.in", "r", stdin);
  18. ios_base::sync_with_stdio(0), cin.tie(0);
  19. int t = 1;
  20. // cin >> t;
  21. while(t--) solve();
  22. return 0;
  23. }
  24.  
  25. ll ans, n, m, last[1000005], p, version;
  26. ll is[1000005];
  27.  
  28. void solve() {
  29. cin >> n >> m >> p;
  30. ll prefix[n + 15][m + 15];
  31. for (ll i = 0; i <= n; ++i) {
  32. for (ll j = 0; j <= m; ++j) {
  33. prefix[i][j] = 0;
  34. }
  35. }
  36. for (ll i = 1; i <= n; ++i) {
  37. for (ll j = 1; j <= m; ++j) {
  38. ll t;
  39. cin >> t;
  40. prefix[i][j] = prefix[i - 1][j] + prefix[i][j - 1] - prefix[i - 1][j - 1] + t;
  41. }
  42. }
  43. if (n <= m) {
  44. for (ll i = 1; i <= n; ++i) {
  45. for (ll j = i; j <= n; ++j) {
  46. ++version;
  47. for (ll z = 1; z <= m; ++z) {
  48. ll sum = prefix[j][z] - prefix[i - 1][z];
  49. if (sum % p == 0) {
  50. ans = max(ans, sum);
  51. continue;
  52. }
  53. if (is[sum % p] == version) {
  54. ll sum2 = prefix[j][last[sum % p]] - prefix[i - 1][last[sum % p]];
  55. ans = max(ans, sum - sum2);
  56. } else {
  57. is[sum % p] = version;
  58. last[sum % p] = z;
  59. }
  60. }
  61. }
  62. }
  63. cout << ans << '\n';
  64. } else {
  65. for (ll i = 1; i <= m; ++i) {
  66. for (ll j = i; j <= m; ++j) {
  67. ++version;
  68. for (ll z = 1; z <= n; ++z) {
  69. ll sum = prefix[z][j] - prefix[z][i - 1];
  70. if (sum % p == 0) {
  71. ans = max(ans, sum);
  72. continue;
  73. }
  74. if (is[sum % p] == version) {
  75. ll sum2 = prefix[last[sum % p]][j] - prefix[last[sum % p]][i - 1];
  76. ans = max(ans, sum - sum2);
  77. } else {
  78. is[sum % p] = version;
  79. last[sum % p] = z;
  80. }
  81. }
  82. }
  83. }
  84. cout << ans << '\n';
  85. }
  86. }
Advertisement
Add Comment
Please, Sign In to add comment
Advertisement