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Jan 21st, 2018
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  1. SELECT DISTINCT(users.uid) AS uid
  2. , og_uid.created AS og_uid_created
  3. FROM users users LEFT JOIN og_uid og_uid ON users.uid = og_uid.uid
  4. WHERE og_uid.nid IN (127998, 128028, 196548, 196558, 196538, 196528, 196568, 128018, 128098, 128068, 128088, 128078, 128058, 128038);
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