3x3 array, store in it, min, max, averarage

#include<iostream.h>
#include<conio.h>
#define m 3
#define n 3
 void main()
 {
   int i, j, sum=0;
   int x[m][n]={{5,6,7},
        {8,9,10},
        {11,12,13},
        };
   float average;
   clrscr();
   for(i=0; i<m; i++)
   for(j=0; j<n; j++)
    {
     cout<<"x["<<i<<"]["<<j<<"]="<<x[i][j]<<endl;
     sum=sum+x[i][j];
    }
     cout<<"sum of the numbers="<<sum<<endl;
     average=sum/(float)(m*n);
     cout<<"average="<<sum<<"/"<<m*n<<endl;
     cout<<"average of the sum="<<average<<endl;
     int min, max;
     int a[9]={5,6,7,8,9,10,11,12,13};

     for(i=0; i<9; i++)
     min=max=a[0];
     for(i=0; i<9; i++)

      {
    if(a[i]>max)
    max=a[i];
      }
       {
    if(a[i]<min)
    min=a[i];
       }
    cout<<" minimum number of the given array="<<min<<endl;
    cout<<" maximum number of the given array="<<max<<endl;

    getch();
 }