2 E

#include <iostream>
#include <vector>
#include <string>
#include <cmath>

using namespace std;

int eq(const string& s1, const string& s2){
    for (int i = 0; i < s1.length(); ++i) {
        if (s1[i] != s2[i]) return 1;
    }

    return 0; // ok
}

int main(){
    ios::sync_with_stdio(false);
    cin.tie(nullptr);

    long long n;
    cin >> n;

    long long m = 1;
    for (long long i = 2; i <= n; ++i) {
        m = (m * i) % 1000000007;
    }

    cout << m;


    return 0;
}