getFileName(ifstream &file)

//============================================================================================================
// getFileName takes a file stream object by reference, and after asking the user for input via a numeric
// choice, executes a switch block, opening 1 of 3 files.
//
// I wanted to have the user type a file name, literally. For example, the user would type "numbers1.txt". I
// wanted that to go into a string, and then call file.open(string);. However as far as I know and from my
// little research on the internet, it turns out ".open()" only takes a string literal as an argument. So I had
// to take the easy way out and just make a switch statement whose .open() function calls already have string
// literals.
// I am not happy with this answer. I want the user to be able to drop any text file into the right folder
// and have the program use it. For example, "clownsandballoons.txt". But until I find out how to do that, this
// is as good as I can do.
//============================================================================================================
void getFileName(ifstream &file)
{
    int choice;
    cout << "Enter 1 to open numbers1.txt, 2 to open numbers2.txt, and 3 to open numbers3.txt\n\t";
    while(cin >> choice, (choice > 3 || choice < 1))
    {
        cout << "Enter 1, 2 or 3.\n\t";
        cin >> choice;
    }
    switch(choice)
    {
    case 1:
        file.open("numbers1.txt");
        break;
    case 2:
        file.open("numbers2.txt");
        break;
    case 3:
        file.open("numbers3.txt");
        break;
    }

    return;
}