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    {
     "name": "stdout",
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     "text": [
      "========================================================\n",
      "Cálculo numérico de la regla del trapecio múltiple\n",
      "========================================================\n",
      "¿Cuál es el número de segmentos? = 4\n",
      "¿Cuál es el valor del límite inferior? = 1\n",
      "¿Cuál es el valor del límite superior? = 2\n",
      "------------------------------------------------------------\n",
      "         n            integral                  et\n",
      "-------------------------------------------------------------\n",
      "         1         6.500000000        12.601127625\n",
      "         2         5.972222222         3.458301023\n",
      "         3         5.863333333         1.571991535\n",
      "         4         5.824070295         0.891828086\n"
     ]
    }
   ],
   "source": [
    "import math\n",
    " \n",
    "print(\"========================================================\")\n",
    "print(\"Cálculo numérico de la regla del trapecio múltiple\")\n",
    "print(\"========================================================\")\n",
    "\n",
    "\n",
    "n=int(input(\"¿Cuál es el número de segmentos? = \"))\n",
    "j=float(input(\"¿Cuál es el valor del límite inferior? = \"))\n",
    "k=float(input(\"¿Cuál es el valor del límite superior? = \"))\n",
    "\n",
    "print(\"------------------------------------------------------------\")\n",
    "print(\"{0:>10s}{1:>20s}{2:>20s}\".format(\"n\", \"integral\", \"et\"))\n",
    "print(\"-------------------------------------------------------------\")\n",
    "\n",
    "vv=5.7725887272\n",
    "fj = ((j+2)/j)**2\n",
    "fk = ((k+2)/k)**2\n",
    "h = (k-j)/n\n",
    "\n",
    "for l in range (n) :\n",
    "    sum=fj\n",
    "    h = (k-j)/(l+1)\n",
    "    for i in range (1,l+1) :\n",
    "        xi = j+(i*h)\n",
    "        fxi = ((xi+2)/xi)**2\n",
    "        sum = sum+(2*fxi)\n",
    "        \n",
    "    sum = sum + fk\n",
    "    sum = h*(sum/2)\n",
    "    et=abs((vv-sum)/vv)*100\n",
    "    print(\"{0:10d}{1:20.9f}{2:20.9f}\".format(l+1, sum , et))\n",
    "\n",
    "    "
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "metadata": {},
   "outputs": [],
   "source": []
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