CSM RMS

import java.text.NumberFormat;
import java.text.DecimalFormat;

public class NewtonRaphson {

    static final double DIFFERENCE = 0.00005;
    double n;
    double x;
    double derivative;
    double function;
    double xold;
    double xnew;
    int i;

    public NewtonRaphson(double n2, int x2) {
        n = n2;
        x = x2;
        function = Math.pow(n, 2) - x;
        derivative = 2 * n;
        xnew = n - function / derivative;
        xold = 0;
    }

    boolean positive() {
        return (n >= 0);
    }

    public double findXNew(double xold2) {
        function = Math.pow(xold2, 2) - x;
        derivative = 2 * xold2;
        return xold2 - function / derivative;
    }

    public void findSqRtA() {

        i = 0;
        while (Math.abs(xnew - xold) > DIFFERENCE) {
            xold = xnew;
            xnew = findXNew(xold);
            i++;
            System.out.println(this);
        }
    }

    public String toString() {
        NumberFormat nf = NumberFormat.getInstance();
        DecimalFormat df
                = (DecimalFormat) nf;
        df.applyPattern("0.00000000");
        return "The approximate value of the square root of " + x + " is "
                + xnew + "\n";

    }
}
import java.io.Console;


import java.util.Scanner;
public class Newton {

    public static void main(String[] args) {
        Scanner reader = new Scanner(System.in);
        System.out.println("Enter a number you would like to find the square root of");
        int a = reader.nextInt();

        NewtonRaphson nr = new NewtonRaphson(5.0, a);

        nr.findSqRtA();

    }
}

*/
OUTPUT :
Enter a number you would like to find the square root of
5
The approximate value of the square root of 5.0 is 2.3333333333333335
The number of iterations is 1
The approximate value of the square root of 5.0 is 2.238095238095238
The number of iterations is 2
The approximate value of the square root of 5.0 is 2.2360688956433634
The number of iterations is 3
The approximate value of the square root of 5.0 is 2.236067977499978
The number of iterations is 4

Iteration completed, difference is less than 0.00005
*/