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desislava_topuzakova

10. Invalid Number начин 3

Nov 12th, 2022
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  1. number = int(input())
  2.  
  3. # валидно: 1. [100;200] или 2. == 0 -> print нищо
  4. # невалидно: print invalid
  5.  
  6. # начин 3
  7. is_valid = 100 <= number <= 200 or number == 0
  8. # is_valid = true -> числото ми е валидно
  9. # is_valid = false -> числото не ми е валидно
  10.  
  11.  
  12. # not is_valid(true) -> false
  13. # not is_valid(false) -> true
  14. if not is_valid:
  15. print("invalid")
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