//найти сумму членов ряда 1 + 1/2 + 1/3 +...+ 1/n

#include <iostream>
using namespace std;

int sum(double n);

int main()
{
	double a;
	cout << "Enter number: " << endl;
	cin >> a;

	cout << sum(a) << endl;

	system("pause");
	return 0;
}

int sum(double n)
{
	double f = 0;
	if (n == 1){
		f = 1;
	}
	else{
		f = 1 / n + sum(n - 1);
	}
	return f;
}