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# mat model

allekco Oct 28th, 2019 67 Never
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1. t = 2700.0 + 273.0
2. T = 2973.0
3. p = 9678.1
4. Cp = 619.0
5. small_lambda = 3.64 #теплопроводность
6. big_lambda = 10196.0
7. m = 0.61 * 0.000001
8. beta = 8.555 * 0.00001 #температурный коэффициент линейного расширения
9. energy = [0.01, 0.1, 0, 10, 100, 1000, 10000, 100000, 1000000, 10000000]
10. sigma_O = [(4, 0.01), (4, 0.1), (4, 0), (4, 10), (5, 100), (1, 1000),
11.            (6, 10000), (6, 100000), (6, 1000000), (6, 10000000)]
12. sigma_f_238 = [(3*10**(-5), 0.01), (10**(-5), 0.1), (3*10**(-6), 0), (7*10**(-7), 10), (10**(-6), 100), (3*10**(-4), 1000),
13.                (2*10**(-4), 10000), (5*10**(-5), 100000), (3*10**(-2), 1000000), (2, 10000000)]
14. sigma_c_238 = [(4, 0.01), (1, 0.1), (5*10**(-1), 0), (9*10**(-1), 10), (3*10, 100), (4, 1000),
15.                (9*10**(-1), 10000), (2*10**(-1), 100000), (1*10**(-1), 1000000), (2*10**(-4), 10000000)]
16. sigma_f_235 = [(10**3, 0.01), (300, 0.1), (80, 0), (70, 10), (20, 100), (9, 1000),
17.                (3, 10000), (2, 100000), (1, 1000000), (2, 10000000)]
18. sigma_c_235 = [(200, 0.01), (40, 0.1), (10, 0), (70, 10), (10, 100), (4, 1000),
19.                (1, 10000), (0.6, 100000), (0.1, 1000000), (10**(-3), 10000000)]
20. Na = 6.022*10**23
21. N_238_nat = Na*19.05*10**6/(0.007*235 + 0.993*238) #metr^(-3)
22. N_235_nat = Na*2.1*10**14/(0.007*235 + 0.993*238)
23. N_238_o = Na*19.05*10**6/270.03
24. N_235_o = Na*2.1*10**17/270.03
25. N_o_o = 2.0*Na*1.4*10**(-3)/270.03
26. Rf_nat = []
27. Rc_nat = []
28. #Rf_o = [10]
29. for i in range(10):
30.     if energy[i] < 1:
31.         fi = 5.0*10**13/0.0001
32.     else:
33.         fi = 2.5*10**13/0.0001
34.     Rf_nat.append(fi * (N_235_nat * sigma_f_235[i][0] + N_238_nat * sigma_f_238[i][0]))
35.
36. for i in range(10):
37.     if energy[i] < 1:
38.         fi = 5.0*10**13/0.0001
39.     else:
40.         fi = 2.5*10**13/0.0001
41.     Rc_nat.append(fi * (N_235_nat * sigma_c_235[i][0] + N_238_nat * sigma_c_238[i][0]))
42.
43. print(*Rc_nat)
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