lsd6 dict 3

import functools


def my_filter(f, d):
    ans = dict()

    def red_funct(prev, curr):
        if f(d[curr]):
            ans[curr] = d[curr]

    functools.reduce(red_funct, d, None)
    return ans


d = {'a': 2, 'c': 33, 'b': 3, 'asd': 11}
print(my_filter(lambda e: e >= 5, d))