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gha890826

a005. Eva 的回家作業

Apr 29th, 2021
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C++ 0.40 KB | None | 0 0
  1. #include<iostream>
  2. using namespace std;
  3.  
  4. int main()
  5. {
  6.     int in[4],a=0;
  7.     cin>>a;
  8.     while(cin>>in[0]>>in[1]>>in[2]>>in[3])
  9.     {
  10.         if((in[2]-in[1]==in[3]-in[2])&&(in[1]-in[0]==in[3]-in[2]))
  11.             {
  12.                 cout<<in[0]<<" "<<in[1]<<" "<<in[2]<<" "<<in[3]<<" "<<in[3]+(in[2]-in[1])<<endl;
  13.             }
  14.         else
  15.             {
  16.                
  17.                 cout<<in[0]<<" "<<in[1]<<" "<<in[2]<<" "<<in[3]<<" "<<in[3]*(in[2]/in[1])<<endl;
  18.             }
  19.     }
  20. }
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