SoftUni bar income

import re

customers = []


def check_name(i: str):
    search = r'%(?P<name>[A-Z][a-z]+)%'
    match = re.search(search, i)
    if match is None:
        return None
    else:
        return match.group('name')


def check_product(i: str):
    search = r'<(?P<item>[\w]+)>'
    match = re.search(search, i)
    if match is None:
        return None
    else:
        return match.group('item')


def check_quantity(i: str):
    search = r'\|(?P<number>[0-9]+)\|'
    match = re.search(search, i)
    if match is None:
        return None
    else:
        return int(match.group('number'))


def check_price(i: str):
    search = r'((?P<price>[0-9]+(\.[0-9]+)*)\$)'
    match = re.search(search, i)
    if match is None:
        return None
    else:
        return float(match.group('price'))


while True:
    info = input()
    if info == 'end of shift':
        break
    name = check_name(info)
    product = check_product(info)
    quantity = check_quantity(info)
    price = check_price(info)
    valid = name and product and quantity and price
    if valid:
        customers.append([name, product, quantity * price])

total_sum = sum([x[2] for x in customers])

# Тук ако ползвам речници няма да стане
# Трябва да принтирам всеки валиден вход дори и да се повтаря, а с речници принтирам само уникални.
[print(f'{x[0]}: {x[1]} - {x[2]:.2f}') for x in customers]
print(f'Total income: {total_sum:.2f}')