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- /*
- Project Euler("https://projecteuler.net/archives")
- Problem 6
- The sum of the squares of the first ten natural numbers is,
- 1^2 + 2^2 + ... + 10^2 = 385
- The square of the sum of the first ten natural numbers is,
- (1 + 2 + ... + 10)^2 = 55^2 = 3025
- Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.
- Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.
- */
- int main(){
- int sumSquares = 0, sumNumbers = 0;
- for(int i = 1; i <= 100; i++){
- sumSquares += i*i;
- sumNumbers += i;
- }
- cout << (sumNumbers * sumNumbers) << " - " << sumSquares << " = " <<(sumNumbers * sumNumbers) - sumSquares << endl;
- system("PAUSE");
- }
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