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Jul 22nd, 2017
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  1. Problem 1:
  2. SELECT publicationname, publicationnamesort FROM sqlb_publicationoverview WHERE publicationname != publicationnamesort;
  3.  
  4. Problem 2:
  5. What is "Arr" (probably from Array (someone uses PHP))
  6. SELECT language0, count(*) FROM sqlb_publicationoverview GROUP BY language0;
  7. vs
  8. SELECT language, count(*) FROM sqlb_publications GROUP BY language;
  9.  
  10.  
  11. Problem 3:
  12. //no unique key :(
  13. SELECT id_pub, COUNT( DISTINCT refcode1 ) FROM sqlb_publications GROUP BY id_pub HAVING COUNT( DISTINCT refcode1 ) > 1;
  14.  
  15. Problem 4:
  16. //parentnote shouldn't be 0... ever
  17. SELECT * FROM sqlb_publications WHERE parentnode IS NOT NULL AND parentnode <= 0 LIMIT 10;
  18.  
  19. Problem 5:
  20. //sha1 passwords needs to be salted
  21. I was able to reverse a few of them
  22. You should consider anything currently stored in there compromised
  23. F7DC00ACEE416C2BEDE7A4AB43FA0623505604A9 -> Sazbir4
  24. 61CAC2F4974BD8DFA6153E4E7B81BF5747BF018C -> thompsond
  25. 011C945F30CE2CBAFC452F39840F025693339C42 -> 1111
  26. 4D7547A1D2787C72F0E985D8B5194295E4AA6141 -> tester1
  27.  
  28. Problem 6:
  29. // 291438 of ~4800000 are wrong?
  30. SELECT count(*) FROM sqlb_publicationoverview
  31. JOIN sqlb_publications ON sqlb_publicationoverview.id_pub = sqlb_publications.id_pub
  32. WHERE sqlb_publicationoverview.publicationcode != sqlb_publications.refcode1;
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