min abs difference between 2 elts array

def generate(n,MAX):
    seen = set()
    for _ in range(MAX):
        seen.add(n)
        if n%2==0 and n/2 not in seen and n/2>0:
            n = n//2
        elif n%2!=0 and n*2 not in seen and n*2<MAX:
            n = n*2
        else:
            continue
    return list(seen)
def getMinDiff(arr, n):
    MAX,MIN = 10,10**9
    # To store the frequency of each element
    freq = [0 for i in range(MAX)]
    for i in range(n):
        # Update the frequency of current element
        for k in generate(arr[i],MAX):
            freq[k] += 1
        # If current element appears more than once then the min abs diff will be 0 i.e. |arr[i] - arr[i]|
        if (freq[k] > 1):
            return 0

    # Checking the distance between the nearest two elements in the frequency array
    for i in range(MAX):
        if (freq[i] > 0):
            i += 1
            cnt = 1
            while ((freq[i] == 0) and (i != MAX - 1)):
                cnt += 1
                i += 1
            MIN = min(cnt, MIN)
            i -= 1
    return MIN, freq
# Driver code
arr = [3, 6, 8]
n = len(arr)
print(getMinDiff(arr, n))