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Jun 18th, 2018
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  1. for (int i = 0; i < n; i++) {
  2. for (int j = i; j < n; j++) {
  3. ll f = 0;
  4. for (int x = i; x <= j; x++)
  5. f = (f * 10 + (s[x] - '0')) % m;
  6. if (GCD(m, f) == 1) ans++;
  7. }
  8. }
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