Numbers that have N divisors on the line (for big lines)

#include<bits/stdc++.h>
#define LINT long long int
using namespace std;
int main() {
    LINT a, b;
    cin >> a >> b;
    vector<vector<LINT>> vc(b + 2);
    for (LINT i = 1; i <= b; ++i)
        for (LINT j = i; j <= b; j += i) {
            vc[j].push_back(i);
        }
    int count;
    cin >> count;
    for (LINT i = a; i <= b; ++i)
        if (vc[i].size() == count) {
            for (auto x : vc[i])
                cout << x << ' ';
            cout << endl;
        }
}