Addictedrobloxs lightning restrained to part

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To see this in action, in your games console do `require(837243090):Init();`
                                                                 _____KEY_______
    * = brick in center of rectangle                            [Width is X Axis]
                                                                [               ]
    ________                                                    [Depth is Z Axis]
   |        |                                                   [_______________]
   |        | Depth = 7
   |        |
   |   *    |
   |        |
   |        |    brick.Position = (0,0,0) ---current position of our brick
   |________|     brick.Size = (4,0,4) -------the current size of our brick
    --------
    Width = 8


 To get to one side, we must add the width of the rectangle divided by 2 to the
position of our brick. Like so:

    brick.Position = brick.Position + Vector3.new(rectangle.Size.X/2,0,0)

Which will put our brick on the right look:

    ________
   |        |
   |        |
   |        |
   |       *|
   |        |
   |        |    brick.Position = (4,0,0) ---current position of our brick
   |________|

Subtracting will have the opposite effect and put it on the left. Now how do we get
to the corner? Well we add half of the depth to our bricks position Like so:

    brick.Position = brick.Position + Vector3.new(0,0,rectangle.Size.Z/2)

This would put the brick at the top right corner, If you want to put the brick insde the
rectangle then you must subtract half of the brick size like so:

    brick.Position=brick.Position+Vector3.new(0,0,((rectangle.Size.Z/2)-(brick.size.Z/2)))

--------------------------------random position inside the brick:-------------------------------

To get a random position inside the rectangle create a function that will math.random the size
of the part, the part is where the lightning will emit from. Once that is done return the
random number as a vector3 (You would of course do this for both X and Z). Imagine i am
saving what the random function returned into the variable called `randPos`, now do this to
place it at a random pos in the obj:

    part.Position = Rectangle.Position+(Vector3.new(((randPos.X-Rectangle.Size.X)+(Rectangle.Size.X/2)),0,((randPos.Z-Rectangle.Size.Z)+(Rectangle.Size.Z/2)))-Vector3.new(0,part.Size.Y/2,0))

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