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Jul 20th, 2017
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  1. #include<iostream.h>
  2. int n, sir[105], i;
  3. void read(int *sir, int &n) {
  4. int i;
  5. cin >> n;
  6. for (i = 1; i <= n; ++i)
  7. cin >> sir[i];
  8. }
  9. int suma_pare(int *sir, int n) {
  10. int s = 0;
  11. int i;
  12. for (i = 1; i <= n; ++i)
  13. if (sir[i] % 2 == 0)
  14. s = s + sir[i];
  15. return s;
  16. }
  17. int suma_pare(int *sir, int n) {
  18. int s = 0;
  19. int i;
  20. for (i = 1; i <= n; ++i)
  21. if (sir[i] % 2 == 0)
  22. s = s + sir[i];
  23. return s;
  24. }
  25. int este_prim(int x) {
  26. int i;
  27. for (i = 2; i * i <= x; ++i)
  28. if (x % i == 0)
  29. return 0;
  30. return 1;
  31. }
  32. void ordoneaza(int *sir, int n) {
  33. int i, j;
  34. for (i = 1; i < n; ++i)
  35. for: ++j)*
  36. if (a[i] > a[j])
  37. {
  38. int aux = a[i];
  39. a[i] = a[j];
  40. a[j] = aux;
  41. }
  42. }
  43. int main() {
  44. read(sir, n);
  45. cout << suma_pare(sir, n) <<endl;
  46. int prime = 0;
  47. for (i = 1; i <= n; ++i)
  48. if (este_prim(sir[i]) == 1)
  49. ++prime;
  50. cout << prime << endl;
  51. ordoneaza(sir, n);
  52. for (i = 1; i <= n; ++i)
  53. cout << sir[i] << " ";
  54. cout << endl;
  55. return 0;
  56. }
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