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Taraxacum

Great Common Divisor

Nov 15th, 2018
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C++ 0.58 KB | None | 0 0
  1. #include <iostream>
  2.  
  3. using namespace std;
  4.  
  5. int gcd1(int m, int n)
  6. {
  7.     for (int div = m > n ? n : m; div >= 1; div--) {
  8.         if (m % div == 0 && n % div == 0) {
  9.             return div;
  10.         }
  11.     }
  12.  
  13.     return 0;
  14. }
  15.  
  16. int gcd2(int m, int n)
  17. {
  18.     if (n == 0) {
  19.         return m;
  20.     } else {
  21.         return gcd2(n, m % n);
  22.     }
  23. }
  24.  
  25. int main()
  26. {
  27.     int m = 18;
  28.     int n = 12;
  29.     cout << m << " " << n << " " << gcd1(m, n) << " " << gcd2(m, n) << endl;
  30.  
  31.     m = 17, n = 18;
  32.  
  33.     cout << m << " " << n << " " << gcd1(m, n) << " " << gcd2(m, n) << endl;
  34. }
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