Check Days of month in a given year

package com.company;

import java.util.Scanner;

public class Main {

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int month = Integer.parseInt(sc.nextLine());
        int year = Integer.parseInt(sc.nextLine());

        //check if year is between 1 and 9999
        if(year <= 0 || year > 9999){
            System.out.println("Wrong year!");
        //check if month is between 1 and 12
        }else if(month <= 0 || month > 12){
            System.out.println("Wrong month!");
        }else{
            System.out.println(daysInMonth(month, year));
        }
    }

    public static int daysInMonth(int month, int year){

        boolean dividedByFour = year % 4 == 0;
        boolean dividedByOneHundred = year % 100 != 0;
        boolean dividedByFourHundred = year % 400 == 0;

        int[] month31Days = {1, 3, 5, 7, 8, 10, 12};

        if(dividedByFour && dividedByOneHundred){
            System.out.println("Leap year");
            for(int i = 0; i < month31Days.length; i++){
                if(month == month31Days[i]) return 31;
                else if (month == 2) return 29;
                else return 30;
            }
        }else if(dividedByFour && dividedByFourHundred){
            System.out.println("Leap year");
            for(int i = 0; i < month31Days.length; i++){
                if(month == month31Days[i]) return 31;
                else if (month == 2) return 29;
                else return 30;
            }
        }

        System.out.println("Not a leap year");
        for(int i = 0; i < month31Days.length; i++){
            if(month == month31Days[i]) return 31;
            else if (month == 2) return 28;
        }
        return 30;
    }
}