bs

    So, I can only really answer this problem conceptually. If the perfect clock ticks along at exactly 1 tick per second, let's say, then the clocked synchronized to the pulsar would slowly tick slower than that. In fact:
    \begin{equation}
        \frac{dt_{pulsar}}{dt} = \frac{P_0}{P}
    \end{equation}
    Because as the period of the pulsar gets larger, it will change slow down the clock. So, presumably through some clever integration and unit cancelling, we can see the result of $t_{pulsar} = (\sqrt{3}-1)P_0/\dot{P_0}$