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Jul 16th, 2020
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  1. \documentclass[11pt,letterpaper]{article}
  2. \usepackage[utf8]{inputenc}
  3. \usepackage{amsmath}
  4. \usepackage{amsfonts}
  5. \usepackage{xcolor}
  6. \usepackage{multicol}
  7. \usepackage{rotating}
  8. \usepackage{amssymb}
  9. \usepackage{graphicx}
  10. \usepackage[left=1cm,right=1cm,top=2cm,bottom=2cm]{geometry}
  11. \makeatletter
  12. \def\tagform@#1{\maketag@@@{[\ignorespaces#1\unskip\@@italiccorr]}}
  13. \makeatother
  14. \newcommand{\fstep}[1]{$$\color{red}{\Downarrow\mbox{Step #1}\Downarrow}$$}
  15. \begin{document}
  16. \begin{sidewaysfigure}
  17. \begin{multicols}{2}
  18. \begin{equation}
  19. ax^2+bx+c=0
  20. \end{equation}
  21. \fstep{1}
  22. \begin{equation}
  23. ax^2+bx=-c
  24. \end{equation}
  25. \fstep{2}
  26. \begin{equation}
  27. x^2+{b\over a}x=-{c\over a}
  28. \end{equation}
  29. \fstep{3}
  30. \begin{equation}
  31. x^2+{b\over a}x+\left({b\over 2a}\right)^2=-{c\over a}+\left({b\over 2a}\right)^2
  32. \end{equation}
  33. \fstep{4}
  34. \begin{equation}
  35. \left(x+{b\over 2a}\right)^2=-{c\over a}+\left({b\over 2a}\right)^2
  36. \end{equation}
  37. \fstep{5}
  38. \begin{equation}
  39. \left(x+{b\over 2a}\right)^2=-{c\over a}+{b^2\over 4a^2}
  40. \end{equation}
  41. \fstep{6}
  42. \begin{equation}
  43. \left(x+{b\over 2a}\right)^2={b^2\over 4a^2}-{c\over a}
  44. \end{equation}
  45. \fstep{7}
  46. \begin{equation}
  47. \left(x+{b\over 2a}\right)^2={b^2\over 4a^2}-{4c\over 4a}
  48. \end{equation}
  49. \fstep{8}
  50. \begin{equation}
  51. \left(x+{b\over 2a}\right)^2={b^2\over 4a^2}-{4ac\over 4a^2}
  52. \end{equation}
  53. \fstep{9}
  54. \begin{equation}
  55. \left(x+{b\over 2a}\right)^2={b^2-4ac\over 4a^2}
  56. \end{equation}
  57. \fstep{10}
  58. \begin{equation}
  59. \sqrt{\left(x+{b\over 2a}\right)^2}=\pm\sqrt{{b^2-4ac\over 4a^2}}
  60. \end{equation}
  61. \fstep{11}
  62. \begin{equation}
  63. x+{b\over 2a}=\pm\sqrt{{b^2-4ac\over 4a^2}}
  64. \end{equation}
  65. \fstep{12}
  66. \begin{equation}
  67. x=-{b\over 2a}\pm\sqrt{{b^2-4ac\over 4a^2}}
  68. \end{equation}
  69. \fstep{13}
  70. \begin{equation}
  71. x=-{b\over 2a}\pm{\sqrt{b^2-4ac}\over 2a}
  72. \end{equation}
  73. \fstep{14}
  74. \begin{equation}
  75. x={-b\pm\sqrt{b^2-4ac}\over 2a}
  76. \end{equation}
  77. \end{multicols}
  78. \end{sidewaysfigure}
  79. \end{document}
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