Advertisement
Guest User

Untitled

a guest
Jun 28th, 2017
79
0
Never
Not a member of Pastebin yet? Sign Up, it unlocks many cool features!
text 0.36 KB | None | 0 0
  1. (: Method 2: return items from $seq1 that do not exist in $seq2 :)
  2. (: most elegant in my opinion :)
  3. let $seq1 := (<el id="a"/>,<el id="2"/>,<el id="3"/>,<el id="4"/>,<el id="5"/>)
  4. let $seq2 := (<el id="a"/>,<el id="b"/>,<el id="c"/>,<el id="d"/>,<el id="1"/>)
  5.  
  6. return
  7.  
  8. $seq1[ fn:not(every $id in @id satisfies $id = $seq2/@id)]
Advertisement
Add Comment
Please, Sign In to add comment
Advertisement