SmelteryFiller

c = peripheral.wrap("top")
m = peripheral.wrap("right")

function fillGold()
  turtle.turnRight()
  turtle.forward()
  turtle.select(1)
  turtle.drop()
  turtle.back()
  turtle.turnLeft()
end

function fillGlass()
  turtle.turnLeft()
  turtle.forward()
  turtle.select(4)
  turtle.drop()
  turtle.back()
  turtle.turnRight()
end

function fillBrass()
  turtle.turnRight()
  turtle.forward()
  turtle.select(2)
  turtle.drop()
  turtle.select(3)
  turtle.drop()
  turtle.back()
  turtle.turnLeft()
end

while true do
  next = true
  i = 1
  gold = 0
  brass = 0
  glass = 0
  fuel = false
  if turtle.getFuelLevel() < 5000 then
    rs.setOutput("front",true)
    os.sleep(0.5)
    rs.setOutput("front",false)
    fuel = true
  end
  while next do
    table = c.getStackInSlot(i)
    if table.qty == nil then
      next = false
    else
      if table.id == 12 then
        glass = tonumber(table.qty)
        turtle.select(4)
      elseif table.id == 9589 then
        turtle.select(3)
      elseif table.id == 20264 then
        brass = (tonumber(table.qty)*4)
        turtle.select(2)
      elseif table.id == 266 then
        gold = (tonumber(table.qty)/2)
        turtle.select(1)
      elseif table.id == 263 then
        turtle.select(5)
      end
      c.swapStacks(i,1)
      turtle.suckUp()
    end
    if gold > 0 then
      m.transmit(500,501,gold)
    end
    if brass > 0 then
      m.transmit(502,501,brass)
    end
    if glass > 0 then
      m.transmit(504,501,glass)
    end
    i = i + 1
  end
  if fuel then
    turtle.select(5)
    turtle.refuel()
  end
  if (gold+brass+glass) > 0 then
    for i = 1, 3 do
      turtle.down()
    end
    turtle.forward()
    turtle.forward()
    if gold > 0 then
      fillGold()
    end
    if glass > 0 then
      fillGlass()
    end
    if brass > 0 then -- Bij 4de smeltery dit uitbreiden
      for i = 1, 7 do
        turtle.forward()
      end
      if brass > 0 then
        fillBrass()
      end
      for i = 1, 7 do
        turtle.back()
      end
    end
    turtle.back()
    turtle.back()
    for i = 1, 3 do
      turtle.up()
    end
  end
  os.sleep(10)
end