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Mar 18th, 2019
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  1. #include<bits/stdc++.h>
  2. using namespace std;
  3.  
  4. #define FOR(i, a, b) for(int i = a; i < b; ++i)
  5. #define REP(i, n) FOR(i, 0, n)
  6. #define _ << " " <<
  7. #define sz(x) ((int) x.size())
  8. #define pb(x) push_back(x)
  9. #define TRACE(x) cerr << #x << " = " << x << endl
  10.  
  11. typedef long long ll;
  12. typedef pair<int, int> point;
  13.  
  14. const int MAXN = 1e6 + 5, mod = 1e9 + 7, baza = 31337;
  15.  
  16. int add(int x, int y) {x += y; if(x >= mod) return x - mod; return x;}
  17. int sub(int x, int y) {x -= y; if(x < 0) return x + mod; return x;}
  18. int mul(int x, int y) {return (ll) x * y % mod;}
  19.  
  20. int h[MAXN], pot[MAXN];
  21.  
  22. int calc(int x, int y){
  23.   int k = 0;
  24.   if(x) k = mul(h[x - 1], pot[y]);
  25.   return sub(h[x + y - 1], k);
  26. }
  27.  
  28. void solve(){
  29.   string s; cin >> s;
  30.   h[0] = s[0];
  31.   pot[0] = 1;
  32.   FOR(i, 1, sz(s)){
  33.     h[i] = add( mul(h[i - 1], baza), s[i]);
  34.     pot[i] = mul(pot[i - 1], baza);
  35.   }
  36.  
  37.   int sol = 0, cnt = 0, last = -1;
  38.   REP(i, sz(s) / 2){
  39.     cnt ++;
  40.  
  41.     if( calc(i - cnt + 1, cnt) == calc(sz(s) - i - 1, cnt)){
  42.       sol += 2;
  43.       cnt = 0;
  44.       last = i;
  45.     }
  46.   }
  47.  
  48.   if(sz(s) % 2) sol ++;
  49.   else if(sz(s) % 2 == 0 && last != sz(s) / 2 - 1) sol ++;
  50.  
  51.   cout << sol << "\n";
  52. }
  53.  
  54. int main(){
  55.   ios_base::sync_with_stdio(false); cin.tie(0);
  56.  
  57.   int t; cin >> t;
  58.   while(t --)
  59.     solve();
  60. }
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