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Sep 19th, 2019
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SQL 0.34 KB | None | 0 0
  1. -- solved with join
  2. SELECT d.department_name, SUM(e.salary) AS dept_total
  3. FROM employees e
  4.      JOIN departments d
  5.      ON (e.department_id = d.department_id)
  6. GROUP BY d.department_name
  7. HAVING SUM(e.salary) > (SELECT SUM(salary)
  8.                         FROM employees) / 8   -- cannot put sum(...) into WHERE!!!
  9. ORDER BY d.department_name;
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