Count occurrences

Count occurrences
Given a non-negative int n, return the count of the occurrences of 7 as a digit, so for example 717 yields 2. (no loops).

Note that mod (%) by 10 yields the rightmost digit (126 % 10 is 6), while divide (/) by 10 removes the rightmost digit (126 / 10 is 12).

Input
On the first line you will be given n.

Output
On the only output line you should print the count of 7s.

Constraints
n>=0

Sample tests
Input
717
Output
2
Input
7
Output
1

import java.util.Scanner;

public class CountOccurrences {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        String input = scanner.nextLine();
        System.out.println(result(input, '7'));
    }

    public static int result(String n, char c ) {
        int count = 0;
        if (n.length() > 0) {
            if (n.charAt(0) == c) {
                count++;
            }
           count += result(n.substring(1), c);
        }
        return count;
    }
}