Advertisement
Not a member of Pastebin yet?
Sign Up,
it unlocks many cool features!
- #include <algorithm>
- #include <cassert>
- #include <climits>
- #include <cmath>
- #include <cstring>
- #include <iomanip>
- #include <iostream>
- #include <limits>
- #include <map>
- #include <queue>
- #include <set>
- #include <stack>
- #include <string>
- #include <unordered_map>
- #include <unordered_set>
- #include <vector>
- #define ll long long
- const int N = 5e3 + 4;
- const int MOD = 1e9 + 7;
- using namespace std;
- int solve() {
- // Your solution logic here
- int n, k;
- cin >> n >> k;
- // Array of +ve integers (1 based indexing)
- vector<int> a(n + 1);
- for (int i = 1; i <= n; i++) {
- cin >> a[i];
- }
- int INF = n + 2;
- vector<vector<int>> dp(
- n + 1, vector<int>(k + 1, INF)); // dp[i][j] = smallest subset with sum =
- // j from the first i elements
- dp[0][0] = 0; // Empty subset
- for (int i = 1; i <= n; i++) {
- // starting from k - a[i] as we add a[i] to each subset
- for (int j = 0; j <= k; j++) {
- if (dp[i - 1][j] != INF) {
- dp[i][j] =
- min(dp[i][j],
- dp[i - 1][j]); // skip adding a[i] in existing subset with sum j
- if (j + a[i] <= k) {
- dp[i][j + a[i]] =
- min(dp[i][j + a[i]],
- dp[i - 1][j] + 1); // try adding a[i] in a subset with sum j
- }
- }
- }
- }
- if (dp[n][k] == INF) {
- cout << "Answer doesn't exist" << endl;
- } else {
- cout << dp[n][k] << endl;
- }
- return 0;
- }
- int main() {
- int t = 1;
- cin >> t;
- while (t--) {
- solve();
- }
- return 0;
- }
Advertisement
Add Comment
Please, Sign In to add comment
Advertisement