>>> a = 100
>>> b = True
>>> print a if b
  File "<stdin>", line 1
    print a if b
             ^
SyntaxError: invalid syntax

if condition: statement
if condition:
    block

expression_if_true if condition else expression_if_false

print a if b else 0

print (a if b else 0)

x = a if b else 0

x = (a if b else 0)

a = 1 if b else 0

a = 1 if b else a

>>> b = True
>>> a = 1 if b else None
>>> a
1
>>> b = False
>>> a = 1 if b else None
>>> a
>>>

>>> if b: print(a)

a = 100
b = True
print a if b else "",  # Note the comma!
print "see no new line"

100 see no new line

from __future__ import print_function
a = False
b = 100
print(b if a else "", end = "")

if logging: print data

[on_true] if [expression] else [on_false]

print a if b else ''

print (1==2 and "only if condition true" or "in case condition is false")

print 1==2 and "aa" or ((2==3) and "bb" or "cc")

>>> print "%d item%s found." % (count, (count>1 and 's' or ''))
1 item found.
>>> count = 2
>>> print "%d item%s found." % (count, (count>1 and 's' or ''))
2 items found.

a=100
b=True

if b:
   print a

print '%s' % (a if b else "")

print '{}'.format(a if b else "")

print(f'{a if b else ""}')

a = b or 0

b = True

b or 0

True

if b:
   print a

a = 1 if b else 0

if b:
    print a
else:
    print 'b is false'

print([a for i in range(0,1) if b])

print([a for a in range(a,a+1) if b])