import os
import argparse
import glob
import sys


class Counter:
	#
	#	This class allows to manage the class CounterLineAndCharacter
	#

	def __init__(self, path):
		self.path = path


	def Run(self):
		if os.path.isfile(str(self.path)):
			Run = CounterLineAndCharacter(self.path)
			return Run.counterlinecharacter()


		elif os.path.isdir(str(self.path)):
			numberline = 0
			numbercharacter = 0
			listfile = listdirectory(self.path)

			#
			#	This loop allows to count the number of line, character of all file
			#
			for file in listfile:
				nl, nc = CounterLineAndCharacter(file).counterlinecharacter()
				numberline += nl
				numbercharacter += nc

			#
			#	This return the number of the line and of the character in all file
			#
			return numberline, numbercharacter


		else:
			raise FileNotFoundError('The file or the folder doesn\'t exists')



class CounterLineAndCharacter:
	#
	#	This class allows to count the lines of a file
	#

	def __init__(self, pathfile):
		self.pathfile = pathfile
		self.file = None
		self.numberline = None
		self.numbercharacter = None


	def counterlinecharacter(self):
		#
		#	This fonction allows to count the number of the line in the file and the number of character
		#	She returns a tuple of int
		#
		with open(self.pathfile, 'r', errors='ignore') as self.file:
			self.numberline = 0
			self.numbercharacter = 0
			for line in self.file:
				self.numbercharacter += len(line)
				if line != '':#						Change here if you want ton a good number of line
					self.numberline += 1


			print('file > '+str(self.pathfile)+' line : '+str(self.numberline)+' || character : '+str(self.numbercharacter))

		return self.numberline, self.numbercharacter


def listdirectory(path):
	fichier=[]
	l = glob.glob(path+'/*')
	for i in l:
		if os.path.isdir(i):
			fichier.extend(listdirectory(i))
		else:
			fichier.append(i.replace('\\', '/'))
	return fichier


if __name__ == '__main__':
	App = Counter(path=sys.argv[1])
	r1, r2 = App.Run()
	print('There are ', r1, 'lines', 'There are ', r2, 'characters')