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Oct 7th, 2017
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SQL 1.16 KB | None | 0 0
  1. sqlite> SELECT c.id, c.fname, COUNT(*)
  2.    ...> FROM customer c INNER JOIN sales_order so
  3.    ...> WHERE c.id = so.cust_id AND c.id IN (
  4.    ...> SELECT s.cust_id
  5.    ...> FROM sales_order s
  6.    ...> WHERE s.sales_rep = 129)
  7.    ...> GROUP BY c.id, c.fname;
  8. 101|Michaels|11
  9. 103|Erin|8
  10. 104|Meghan|11
  11. 107|Kelly|11
  12. 110|Michael|10
  13. 111|Dylan|8
  14. 116|Brian|7
  15. 117|Meredith|8
  16. 119|Tomm|6
  17. 121|Pete|8
  18. 122|Al|6
  19. 126|Sam|5
  20. 127|Mary|6
  21. 128|Hardy|6
  22. 131|Daljit|5
  23. 132|Marilyn|7
  24. 136|Tommie|8
  25. 137|Polly|6
  26. 138|Regus|6
  27. 143|Peter|6
  28. 144|Fangmei|7
  29. 149|Hans|6
  30. 155|Milo|4
  31. 157|William|6
  32. 162|Melba|3
  33. 167|Nicklas|4
  34. 168|Almen|6
  35. 170|Manh|5
  36. 173|Grover|3
  37. 178|Suresh|4
  38. 179|Marsha|4
  39. 180|Edith|4
  40. 182|Leilani|7
  41. 184|Anoush|4
  42. 189|Herbert|8
  43. 190|Randy|7
  44. 191|Marta|6
  45. 194|Jen-Chang|5
  46. 197|Maio|6
  47. 198|Sheng|9
  48. 199|Ella|9
  49. 201|Amit|11
  50. 202|Bubba|8
  51. 204|Robert|11
  52. 205|Elmo|8
  53.  
  54. sqlite> SELECT c.id, c.fname, COUNT(*)
  55.    ...> FROM customer c INNER JOIN sales_order so
  56.    ...> ON c.id = so.cust_id
  57.    ...> GROUP BY c.id, c.fname
  58.    ...> HAVING so.sales_rep = 129;
  59. 121|Pete|8
  60. 127|Mary|6
  61. 131|Daljit|5
  62. 137|Polly|6
  63. 157|William|6
  64. 170|Manh|5
  65. 173|Grover|3
  66. 194|Jen-Chang|5
  67. 199|Ella|9
  68. 205|Elmo|8
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