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Nov 26th, 2018
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  1. pi_4(1, Pi) -> Pi;
  2. pi_4(K, Pi) ->
  3.     case K rem 2 of
  4.         1 -> pi_4(K-1, Pi+1/(2*K-1));
  5.         0 -> pi_4(K-1, Pi-1/(2*K-1))
  6.     end.
  7. pi(K) -> 4*pi_4(K, 1).
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