// #pragma GCC optimize("Ofast,no-stack-protector,unroll-loops,fast-math")
// #pragma GCC target("sse,sse2,sse3,ssse3,sse4,sse4.1,sse4.2,popcnt,abm,mmx,avx")
// #pragma comment(linker, "/stack:200000000"]

#include <iostream>
#include <vector>
#include <cmath>
#include <algorithm>
#include <unordered_set>
#include <unordered_map>
#include <set>
#include <map>
#include <queue>
#include <deque>
#include <bitset>
#include <stack>
#include <random>
#include <fstream>
#include <sstream>
#include <chrono>

#define fi first
#define se second
#define pb push_back
#define ll long long
#define ld long double
#define hm unordered_map
#define pii pair<int, int>
#define sz(a) (int)a.size()
#define all(a) a.begin(), a.end()
#define cinv(v) for (auto& x: v) cin >> x
#define fr(i, n) for (int i = 0; i < n; ++i)
#define fl(i, l, n) for (int i = l; i < n; ++i)

#define int ll

template <typename T1, typename T2> inline bool chkmin(T1 &x, const T2 &y) {if (x > y) {x = y; return 1;} return 0;}
template <typename T1, typename T2> inline bool chkmax(T1 &x, const T2 &y) {if (x < y) {x = y; return 1;} return 0;}

using namespace std;

#ifdef LOCAL
	#define dbg(x) cerr << #x << " : " << x << '\n'
	const int maxn = 20;
#else
	#define dbg(x)
	const int maxn = 1e5 + 20;
#endif

//tg: @galebickosikasa

ostream& operator << (ostream& out, const pii& v) {
	out << v.fi << ", " << v.se;
	return out;
}

template<typename T> ostream& operator << (ostream& out, const vector<T>& v) {
    for (auto& x: v) out << x << " ";
    return out;
}

istream& operator >> (istream& in, pii& a) {
	in >> a.fi >> a.se;
	return in;
}

const ll inf = (ll) 2e9;
const ld pi = asin (1) * 2;
const ld eps = 1e-8;
const ll mod = (ll)1e9 + 7;
const ll ns = 97;

mt19937 rnd(chrono::steady_clock::now().time_since_epoch().count());

ll mult (ll a, ll b) {
	return a * b % mod;
}

ll add (ll a, ll b) {
	int c = a + b;
	if (c >= mod) c -= mod;
	return c;
}

ll powmod (ll a, ll n) {
	if (n == 0) return 1;
	if (n % 2) return mult (a, powmod (a, n - 1));
	ll b = powmod (a, n / 2);
	return mult (b, b);
}

ll inv (int a) {
	return powmod (a, mod - 2);
}

int f[maxn], rev[maxn];

int C (int n, int k) {
	return mult (mult (f[n], rev[k]), rev[n - k]);
}

signed main () {
	ios_base::sync_with_stdio(false);
	cin.tie(nullptr);
	cout.tie(nullptr);
	int n;
	cin >> n;
	n /= 2;
	f[0] = 1;
	fl (i, 1, maxn) f[i] = mult (f[i - 1], i);
	rev[maxn - 1] = inv (f[maxn - 1]);
	for (int i = maxn - 2; i >= 0; --i) rev[i] = mult (rev[i + 1], i + 1);
	int ans = mult (C (2 * n, n), inv (n + 1));
	cout << ans << '\n';






}