15 множества наименьшее A

#4879 https://kpolyakov.spb.ru/school/ege/gen.php?action=viewAllEgeNo&egeId=15&cat68=on
answ = 0
p = {1, 2, 4, 8}
q = {1, 2, 3, 4, 5, 6}
for x in range(-1000, 1000):
    if ((not (0)) <= (not((x in p) or (x in q)))) == 0:
        answ += 1
print(answ)