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Jun 27th, 2017
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  1. SELECT k.nazwa_kl FROM klienci2 k join zamowienia2 z on k.id_kl = z.id_kl having count(z.id_kl) >
  2. ( SELECT count(z.id_kl) FROM klienci2 k join zamowienia2 z on k.id_kl = z.id_kl WHERE k.nazwa_kl = 'Zaklady C' )
  3. group by k.nazwa_kl;
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